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Calculate the equilibrium constant for the reaction : `Fe^(2+)+Ce^(4+)hArr Fe^(3+)+Ce^(3+)` Given, `E_(Ca^(4+)//Ce^(3+))^(@)=1.44V` and `E_(Fe^(3+)//Fe^(2+))^(@)=0.68V`

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`7.6 xx 10^12`
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RC MUKHERJEE-MISCELLANEOUS PROBLEMS FOR REVISION-SUBJECTIVE TYPE QUESTIONS
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