Calculate the percentage of hydrolysis in 0.003 M aqueous solution of NaOCN. `K_a` for HOCN `= 3.33 xx 10^(-4) M` .

Explanation

To calculate the percentage of hydrolysis in a 0.003 M aqueous solution of NaOCN, we need to follow these steps:

### Step 1: Identify the relevant constants
We know that:
- The dissociation constant of water, \( K_w = 1.0 \times 10^{-14} \, M^2 \)
- The dissociation constant of the weak acid \( HOCN \), \( K_a = 3.33 \times 10^{-4} \, M \)

### Step 2: Calculate \( K_b \) for the conjugate base \( OCN^- \)
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