A sample of U^(238) ("half life" = 4.5 x...

A sample of `U^(238) ("half life" = 4.5 xx 10^(9)yr)` ore is found to contain `23.8 g" of " U^(238) ` and `20.6g ` of `Pb^(206)`. Calculate the age of the ore

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`4.489 xx 10^9 `years

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A sample of U^(238) (half-line = 4.5xx10^(9) yr ) ore is found to contain 23.8g of U^(238) and 20.6g of Pb^(206) Calculate the age of the ore.

Uranium ( ""_(92)U""^(238) ) decayed to ""_(82)Pb""^(206) . The process is ""_(92)U""^(238)underset(xalpha,ybeta)to.""_(82)Pb""^(206) t""_(1//2)of U""^(238)=4.5xx10""^(9) years A sample of rock from South America contains equal number of atoms of U""^(238) and Pb""^(""^(206) . The age of the rock will be

Uranium ._(92)U^(238) decayed to ._(82)Pb^(206) . They decay process is ._(92)U^(238) underset((x alpha, y beta))(rarr ._(82)Pb^(206)) t_(1//2) of U^(238) = 4.5 xx 10^(9) years The analysis of a rock shows the relative number of U^(238) and Pb^(206) atoms (Pb//U = 0.25) The age of rock will be

^238U decays to ^206(Pb) with a half-life of 4.47xx10^9 y.This happens in a number of steps .Can you justify a single half-life for this chain of processes? A sample of rock is found to contain 2.00mg of 238U and 0.600 mg of 206(Pb) .assuming that all the lead has come form uranium ,find the life of the rock.

(a) On analysis a sample of uranium ore was found to contian 0.277g of ._(82)Pb^(206) and 1.667g of ._(92)Pb^(206) and 1.667g of ._(92)U^(238) . The half life period of U^(238) is 4.51xx10^(9) year. IF all the lead were assumed to have come from decay of ._(92)U^(238) , What is the age of earth? (b) An ore of ._(92)U^(238) is found to contain ._(92)U^(238) and ._(82)Pb^(206) in the weight ratio of 1: 0.1 The half-life period of ._(92)U^(238) is 4.5xx10^(9) year. Caluculate the age of ore.

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