Copper sulphate solution `(250 ML)` was electrolyzed using a platinum anode and a copper cathode. A constant current of `2mA` was passed for `16 mi n`. It was found that after electrolysis the absorbance of the solution was reducted to `50%` of its original value . Calculate the concentration of copper sulphate in the solution to begin with.

Explanation

Initial mole of `CuSO_4` per 250 ml
`= 2 xx` mole of `CuSO_4` lost
2 x mol of Cu deposited
`7.958 xx 10^(-5) M`