What is the half-life for the decomposition of NOCI when the concentration of NOCI is 0.15 M? The rate constant for the reaction is `8.0 xx 10^(-8) L "mol"^(-1) s^(-1)`

Explanation

To find the half-life of the decomposition of NOCl, which is a second-order reaction, we can use the formula for the half-life of a second-order reaction:

\[ t_{1/2} = \frac{1}{k \cdot [A]_0} \]

Where:
- \( t_{1/2} \) is the half-life,
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