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0.1 M of HA is titrated with 0.1 M NaOH,...

0.1 M of HA is titrated with 0.1 M NaOH, calculate the pH at end point. Given `K_(a)(HA)=5xx10^(-5)` and `alpha lt lt 1`

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Apply pH ` = 1/2 [pK_w + pK_a + log a] , a = (0.1)/(2) M`
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