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If T(1)andT(2) are the temperatures of t...

If `T_(1)andT_(2)` are the temperatures of the heat source and sink respectively, the efficiency of a heat engine may be expressed as

A

`(T_(2)-T_(1))/T_(2)`

B

`T_(1)/T_(2)`

C

`(T_(1)-T_(2))/T_(1)`

D

`T_(2)/T_(1)`

Text Solution

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The correct Answer is:
To derive the efficiency of a heat engine based on the temperatures of the heat source and sink, we can follow these steps: ### Step 1: Understand the Concept of Efficiency The efficiency (\( \eta \)) of a heat engine is defined as the ratio of the work output to the heat input. It can also be expressed in terms of the temperatures of the heat source (\( T_1 \)) and the heat sink (\( T_2 \)). ### Step 2: Identify Wastage The heat engine operates between two temperatures: the higher temperature \( T_1 \) (heat source) and the lower temperature \( T_2 \) (heat sink). The wastage of energy occurs as heat is transferred to the sink. ### Step 3: Write the Efficiency Formula The efficiency can be expressed as: \[ \eta = \frac{\text{Work output}}{\text{Heat input}} = 1 - \frac{Q_{out}}{Q_{in}} \] Where: - \( Q_{in} \) is the heat absorbed from the heat source (\( T_1 \)) - \( Q_{out} \) is the heat rejected to the sink (\( T_2 \)) ### Step 4: Relate Heat Transfer to Temperatures For a reversible heat engine, the heat transferred can be related to the temperatures: \[ \eta = 1 - \frac{T_2}{T_1} \] ### Step 5: Express Efficiency in Percentage To express the efficiency in percentage, we multiply by 100: \[ \text{Percentage Efficiency} = \left(1 - \frac{T_2}{T_1}\right) \times 100 \] ### Final Result Thus, the efficiency of the heat engine can be expressed as: \[ \eta = 1 - \frac{T_2}{T_1} \] And the percentage efficiency can be expressed as: \[ \text{Percentage Efficiency} = \left(1 - \frac{T_2}{T_1}\right) \times 100 \]
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