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The equivalent weight of HNO(3) (molecul...

The equivalent weight of `HNO_(3)` (molecular weight `=63`) in the following reaction is
`3Cu+8HNO_(3)rarr3Cu(NO_(3))_(2)+2NO+4H_(2)O`

A

`(4xx63)/3`

B

`63/5`

C

`63/3`

D

`63/8`

Text Solution

Verified by Experts

The correct Answer is:
A

Out of 8 N atoms in `HNO_(3)`, only 2 N atoms undergo reduction to NO. Further, 6 moles of electrons are involved with 8 moles of `HNO_(3)`.
`E=M+M/3=8/6M,M=63`
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