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In a first-order reaction of the type: A...

In a first-order reaction of the type: `A(g)to2B(g)`, the initial and final pressures are `P_(1)` and p respectively. The rate constant can be expressed by

A

`k=1/t"ln"(p_(1))/(2p_(1)-p)`

B

`k=1/t"ln"(p_(1))/(p_(1)-p)`

C

`k=1/t"ln"(p_(1))/(p-p_(1))`

D

`k=1/t"ln"(p_(1))/(p)`

Text Solution

AI Generated Solution

The correct Answer is:
To determine the rate constant for the first-order reaction \( A(g) \to 2B(g) \) in terms of the initial and final pressures, we can follow these steps: ### Step 1: Understand the Reaction In this reaction, one mole of gas A produces two moles of gas B. This means that if we start with \( P_1 \) as the initial pressure of A, the change in pressure will affect the total pressure of the system. ### Step 2: Define the Changes in Pressure Let \( x \) be the amount of A that reacts. Therefore, the change in pressure due to the reaction can be expressed as: - The pressure of A decreases by \( x \) (since 1 mole of A produces 2 moles of B). - The pressure of B increases by \( 2x \). ### Step 3: Express the Final Pressure The final pressure \( P \) can be expressed in terms of the initial pressure \( P_1 \) and the change \( x \): \[ P = P_1 - x + 2x = P_1 + x \] This simplifies to: \[ x = P - P_1 \] ### Step 4: Relate the Change to the Rate Constant For a first-order reaction, the rate equation is given by: \[ \frac{d[A]}{dt} = -k[A] \] Integrating this for a first-order reaction gives us: \[ \ln\left(\frac{[A]_0}{[A]}\right) = kt \] Where \( [A]_0 \) is the initial concentration and \( [A] \) is the concentration at time \( t \). ### Step 5: Substitute Pressure for Concentration Since pressure is directly proportional to concentration for gases, we can substitute pressures into the equation: \[ \ln\left(\frac{P_1}{P - P_1}\right) = kt \] Where \( P - P_1 \) represents the pressure of A at time \( t \). ### Step 6: Solve for the Rate Constant \( k \) Rearranging the equation gives us: \[ k = \frac{1}{t} \ln\left(\frac{P_1}{P - P_1}\right) \] ### Final Expression Thus, the rate constant \( k \) for the reaction can be expressed as: \[ k = \frac{1}{t} \ln\left(\frac{P_1}{P - P_1}\right) \]
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