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0.8 g of silver salt of a dibasic organi...

0.8 g of silver salt of a dibasic organic acid on ignition yielded 0.54 g of metallic silver. Molecular weight of the acid is (Ag = 108)

A

106

B

108

C

320

D

85

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AI Generated Solution

The correct Answer is:
To solve the problem step-by-step, we will follow these steps: ### Step 1: Understand the Reaction We have a dibasic organic acid (H₂A) that forms a silver salt (Ag₂A). On ignition, this salt yields metallic silver (Ag). The mass of the silver salt is given as 0.8 g, and the mass of the metallic silver produced is 0.54 g. ### Step 2: Determine the Molar Mass of Silver The atomic mass of silver (Ag) is given as 108 g/mol. ### Step 3: Calculate the Moles of Silver Produced Using the mass of silver produced, we can calculate the number of moles of silver: \[ \text{Moles of Ag} = \frac{\text{mass of Ag}}{\text{molar mass of Ag}} = \frac{0.54 \, \text{g}}{108 \, \text{g/mol}} = 0.005 \, \text{mol} \] ### Step 4: Relate Moles of Silver to Moles of Silver Salt Since the silver salt is Ag₂A, each mole of Ag₂A produces 2 moles of Ag. Therefore, the moles of silver salt (Ag₂A) can be calculated as: \[ \text{Moles of Ag₂A} = \frac{\text{Moles of Ag}}{2} = \frac{0.005 \, \text{mol}}{2} = 0.0025 \, \text{mol} \] ### Step 5: Calculate the Molar Mass of the Silver Salt Now we can find the molar mass of the silver salt (Ag₂A) using the mass and moles calculated: \[ \text{Molar mass of Ag₂A} = \frac{\text{mass of Ag₂A}}{\text{moles of Ag₂A}} = \frac{0.8 \, \text{g}}{0.0025 \, \text{mol}} = 320 \, \text{g/mol} \] ### Step 6: Set Up the Equation for Molar Mass of the Acid The molar mass of the silver salt (Ag₂A) can be expressed as: \[ \text{Molar mass of Ag₂A} = 2 \times \text{molar mass of Ag} + \text{molar mass of A} \] Substituting the values we have: \[ 320 \, \text{g/mol} = 2 \times 108 \, \text{g/mol} + X \] Where \(X\) is the molar mass of the anion A. ### Step 7: Solve for the Molar Mass of A Calculating the equation: \[ 320 = 216 + X \] \[ X = 320 - 216 = 104 \, \text{g/mol} \] ### Step 8: Calculate the Molar Mass of the Dibasic Acid (H₂A) The molar mass of the dibasic acid (H₂A) is given by: \[ \text{Molar mass of H₂A} = 2 \times 1 + X = 2 + 104 = 106 \, \text{g/mol} \] ### Final Answer The molecular weight of the dibasic organic acid (H₂A) is **106 g/mol**. ---
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