Solubility product of silver bromide is `5.0xx10^(-13)`. The quantity of potassium bromide (molar mass taken as `120g mol^(-1)`) to be added to `1 L` of `0.05 M` solution of silver nitrate to start the precipitation of `AgBr` is

Options

A. `1.2xx10^(-10)g`
B. `1.2xx10^(-9)g`
C. `6.2xx10^(-5)g`
D. `5.0xx10^(-8)g`

Answer

B

Explanation

Wt. in g = no. of moles `xx` mol. Wt.