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If z is a purely imaginary number then a...

If z is a purely imaginary number then arg (z) may be

A

0 or `pi`

B

`-pi` or 0

C

`pi or pi`

D

`-(pi)/(2)` or `(pi)/(2)`

Text Solution

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The correct Answer is:
To solve the question, we need to determine the argument of a purely imaginary number \( z \). ### Step-by-Step Solution: 1. **Understanding Purely Imaginary Numbers**: A purely imaginary number can be expressed in the form: \[ z = 0 + ib \] where \( b \) is a real number and \( i \) is the imaginary unit. 2. **Identifying the Real and Imaginary Parts**: From the expression \( z = ib \), we can identify: - Real part \( \text{Re}(z) = 0 \) - Imaginary part \( \text{Im}(z) = b \) 3. **Using the Argument Formula**: The argument of a complex number \( z \) is given by: \[ \text{arg}(z) = \theta \] where \( \tan(\theta) = \frac{\text{Im}(z)}{\text{Re}(z)} \). 4. **Calculating the Argument**: Substituting the real and imaginary parts into the formula: \[ \tan(\theta) = \frac{b}{0} \] Since the real part is zero, this expression is undefined, which implies that \( \tan(\theta) \) approaches infinity. 5. **Determining the Angles**: The tangent function approaches infinity at the angles: \[ \theta = \frac{\pi}{2} \quad \text{or} \quad \theta = -\frac{\pi}{2} \] Therefore, the argument of a purely imaginary number can be either \( \frac{\pi}{2} \) or \( -\frac{\pi}{2} \). ### Final Answer: Thus, the argument of \( z \) when \( z \) is a purely imaginary number may be: \[ \text{arg}(z) = \frac{\pi}{2} \quad \text{or} \quad -\frac{\pi}{2} \]
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