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If z is a complex number then...

If z is a complex number then

A

`|z^(2)| gt |z|^(2)`

B

`|z|^(2)gt |z^(2)|`

C

`|z^(2)|=|z|^(2)`

D

`|z^(2)|gt= |z|^(2)`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to analyze the properties of complex numbers and their moduli. Let's denote the complex number \( z \) as \( z = x + iy \), where \( x \) and \( y \) are real numbers. ### Step 1: Calculate \( z^2 \) First, we compute \( z^2 \): \[ z^2 = (x + iy)^2 = x^2 + 2xyi - y^2 = (x^2 - y^2) + 2xyi \] ### Step 2: Calculate the modulus of \( z^2 \) Next, we find the modulus of \( z^2 \): \[ |z^2| = |(x^2 - y^2) + 2xyi| = \sqrt{(x^2 - y^2)^2 + (2xy)^2} \] Calculating the expression inside the square root: \[ |z^2| = \sqrt{(x^2 - y^2)^2 + 4x^2y^2} \] ### Step 3: Calculate \( |z|^2 \) Now, we calculate \( |z|^2 \): \[ |z| = |x + iy| = \sqrt{x^2 + y^2} \] Thus, \[ |z|^2 = x^2 + y^2 \] ### Step 4: Calculate \( |z|^2 \) squared Next, we compute \( |z|^2 \) squared: \[ |z|^4 = (x^2 + y^2)^2 = x^4 + 2x^2y^2 + y^4 \] ### Step 5: Compare \( |z^2| \) and \( |z|^2 \) Now we need to compare \( |z^2|^2 \) and \( |z|^4 \): \[ |z^2|^2 = (x^2 - y^2)^2 + 4x^2y^2 \] Expanding \( |z^2|^2 \): \[ |z^2|^2 = (x^4 - 2x^2y^2 + y^4) + 4x^2y^2 = x^4 + 2x^2y^2 + y^4 \] Thus, we find: \[ |z^2|^2 = |z|^4 \] ### Conclusion From the calculations, we have shown that: \[ |z^2|^2 = |z|^4 \] This leads us to conclude that: \[ |z^2| = |z|^2 \] Thus, the statement \( |z^2| \) is equal to \( |z|^2 \) is verified.
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