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Equation of a circle which passes thro...

Equation of a circle which passes through (3,6) and touches the axes is

A

`x^(2) + y^(2) + 6x + 6y + 3 = 0 `

B

` x^(2) + y^(2) - 6x - 6y - 9 = 0 `

C

` x^(2) + y^(2) - 6x - 6y + 9 = 0 `

D

none of these

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The correct Answer is:
To find the equation of a circle that passes through the point (3, 6) and touches both the axes, we can follow these steps: ### Step 1: Understand the properties of the circle Since the circle touches both the axes, its center must be at a point (a, a) where 'a' is the radius of the circle. This is because the distance from the center to each axis must equal the radius. ### Step 2: Write the general equation of the circle The equation of a circle with center (a, a) and radius a is given by: \[ (x - a)^2 + (y - a)^2 = a^2 \] ### Step 3: Substitute the point (3, 6) into the equation Since the circle passes through the point (3, 6), we can substitute x = 3 and y = 6 into the circle's equation: \[ (3 - a)^2 + (6 - a)^2 = a^2 \] ### Step 4: Expand the equation Now, let's expand the left-hand side: \[ (3 - a)^2 = 9 - 6a + a^2 \] \[ (6 - a)^2 = 36 - 12a + a^2 \] Combining these, we have: \[ 9 - 6a + a^2 + 36 - 12a + a^2 = a^2 \] This simplifies to: \[ 2a^2 - 18a + 45 = a^2 \] ### Step 5: Rearrange the equation Now, we will rearrange the equation: \[ 2a^2 - 18a + 45 - a^2 = 0 \] This simplifies to: \[ a^2 - 18a + 45 = 0 \] ### Step 6: Solve the quadratic equation To solve the quadratic equation \( a^2 - 18a + 45 = 0 \), we can factor it: \[ (a - 3)(a - 15) = 0 \] Thus, we find: \[ a = 3 \quad \text{or} \quad a = 15 \] ### Step 7: Write the equations of the circles 1. For \( a = 3 \): \[ (x - 3)^2 + (y - 3)^2 = 3^2 \] Expanding this gives: \[ x^2 - 6x + 9 + y^2 - 6y + 9 = 9 \] Simplifying, we get: \[ x^2 + y^2 - 6x - 6y + 9 = 0 \] 2. For \( a = 15 \): \[ (x - 15)^2 + (y - 15)^2 = 15^2 \] Expanding this gives: \[ x^2 - 30x + 225 + y^2 - 30y + 225 = 225 \] Simplifying, we get: \[ x^2 + y^2 - 30x - 30y + 225 = 0 \] ### Final Result The equations of the circles that pass through (3, 6) and touch both axes are: 1. \( x^2 + y^2 - 6x - 6y + 9 = 0 \) 2. \( x^2 + y^2 - 30x - 30y + 225 = 0 \)
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