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Find the prime factorisation of the numb...

Find the prime factorisation of the numbers :
`6000`

A

`2 times 2times 2 times 2 times 3 times 5 times 5 `

B

`2 times 2times 2 times 2 times 2 times 5 times 5 `

C

`2 times 2times 2 times 2 times 3 times 5 times 7 `

D

`2 times 2times 2 times 2 times 3 times 3 times 5 `

Text Solution

AI Generated Solution

The correct Answer is:
To find the prime factorization of the number 6000, we will follow a systematic approach of dividing the number by its smallest prime factors until we reach 1. Here’s how we can do it step by step: ### Step 1: Start with the number 6000 We begin with the number 6000. ### Step 2: Divide by the smallest prime number Since 6000 is an even number, we can divide it by 2 (the smallest prime number). \[ 6000 \div 2 = 3000 \] ### Step 3: Continue dividing by 2 Now, we divide 3000 by 2 again since it is still even. \[ 3000 \div 2 = 1500 \] ### Step 4: Divide by 2 again Next, we divide 1500 by 2. \[ 1500 \div 2 = 750 \] ### Step 5: Divide by 2 once more We continue dividing by 2. \[ 750 \div 2 = 375 \] ### Step 6: Divide by the next smallest prime number 375 is not even, so we try the next smallest prime number, which is 3. We check if 375 is divisible by 3: \[ 3 + 7 + 5 = 15 \quad (\text{which is divisible by } 3) \] Now, we divide: \[ 375 \div 3 = 125 \] ### Step 7: Divide by 5 Next, we divide 125 by 5 (the next smallest prime number). \[ 125 \div 5 = 25 \] ### Step 8: Divide by 5 again We divide 25 by 5. \[ 25 \div 5 = 5 \] ### Step 9: Divide by 5 one last time Finally, we divide 5 by 5. \[ 5 \div 5 = 1 \] ### Step 10: Write down the prime factors Now, we can write down all the prime factors we used: - We divided by 2 four times: \( 2 \times 2 \times 2 \times 2 \) or \( 2^4 \) - We divided by 3 once: \( 3 \) - We divided by 5 three times: \( 5 \times 5 \times 5 \) or \( 5^3 \) ### Final Prime Factorization Putting it all together, the prime factorization of 6000 is: \[ 6000 = 2^4 \times 3^1 \times 5^3 \]
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