To find the first six multiples of the given natural numbers (3, 5, and 12), we will multiply each number by the integers from 1 to 6.
### Step-by-Step Solution:
**(i) First six multiples of 3:**
1. **Multiply 3 by 1:**
\( 3 \times 1 = 3 \)
First multiple is **3**.
2. **Multiply 3 by 2:**
\( 3 \times 2 = 6 \)
Second multiple is **6**.
3. **Multiply 3 by 3:**
\( 3 \times 3 = 9 \)
Third multiple is **9**.
4. **Multiply 3 by 4:**
\( 3 \times 4 = 12 \)
Fourth multiple is **12**.
5. **Multiply 3 by 5:**
\( 3 \times 5 = 15 \)
Fifth multiple is **15**.
6. **Multiply 3 by 6:**
\( 3 \times 6 = 18 \)
Sixth multiple is **18**.
So, the first six multiples of 3 are: **3, 6, 9, 12, 15, 18**.
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**(ii) First six multiples of 5:**
1. **Multiply 5 by 1:**
\( 5 \times 1 = 5 \)
First multiple is **5**.
2. **Multiply 5 by 2:**
\( 5 \times 2 = 10 \)
Second multiple is **10**.
3. **Multiply 5 by 3:**
\( 5 \times 3 = 15 \)
Third multiple is **15**.
4. **Multiply 5 by 4:**
\( 5 \times 4 = 20 \)
Fourth multiple is **20**.
5. **Multiply 5 by 5:**
\( 5 \times 5 = 25 \)
Fifth multiple is **25**.
6. **Multiply 5 by 6:**
\( 5 \times 6 = 30 \)
Sixth multiple is **30**.
So, the first six multiples of 5 are: **5, 10, 15, 20, 25, 30**.
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**(iii) First six multiples of 12:**
1. **Multiply 12 by 1:**
\( 12 \times 1 = 12 \)
First multiple is **12**.
2. **Multiply 12 by 2:**
\( 12 \times 2 = 24 \)
Second multiple is **24**.
3. **Multiply 12 by 3:**
\( 12 \times 3 = 36 \)
Third multiple is **36**.
4. **Multiply 12 by 4:**
\( 12 \times 4 = 48 \)
Fourth multiple is **48**.
5. **Multiply 12 by 5:**
\( 12 \times 5 = 60 \)
Fifth multiple is **60**.
6. **Multiply 12 by 6:**
\( 12 \times 6 = 72 \)
Sixth multiple is **72**.
So, the first six multiples of 12 are: **12, 24, 36, 48, 60, 72**.
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### Summary of Results:
- First six multiples of 3: **3, 6, 9, 12, 15, 18**
- First six multiples of 5: **5, 10, 15, 20, 25, 30**
- First six multiples of 12: **12, 24, 36, 48, 60, 72**
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