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Write the set of factors of : (i) 88 "...

Write the set of factors of :
(i) 88 `" "` (ii) 105 `" "` (iii) 96

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To find the set of factors for the numbers 88, 105, and 96, we can use the prime factorization method. Here’s a step-by-step solution for each number: ### (i) Factors of 88 1. **Start with the number 88.** 2. **Divide by the smallest prime number (2):** - 88 ÷ 2 = 44 3. **Continue dividing by 2:** - 44 ÷ 2 = 22 4. **Continue dividing by 2:** - 22 ÷ 2 = 11 5. **11 is a prime number, so we divide by 11:** - 11 ÷ 11 = 1 6. **List all the factors:** - From the divisions, we can find the factors: - 1, 2, 4 (2×2), 8 (2×2×2), 11, 22 (2×11), 44 (4×11), 88 (8×11). **Set of factors of 88:** {1, 2, 4, 8, 11, 22, 44, 88} ### (ii) Factors of 105 1. **Start with the number 105.** 2. **Divide by the smallest prime number (3):** - 105 ÷ 3 = 35 3. **Next, divide by 5:** - 35 ÷ 5 = 7 4. **7 is a prime number, so we divide by 7:** - 7 ÷ 7 = 1 5. **List all the factors:** - From the divisions, we can find the factors: - 1, 3, 5, 7, 15 (3×5), 21 (3×7), 35 (5×7), 105 (3×5×7). **Set of factors of 105:** {1, 3, 5, 7, 15, 21, 35, 105} ### (iii) Factors of 96 1. **Start with the number 96.** 2. **Divide by the smallest prime number (2):** - 96 ÷ 2 = 48 3. **Continue dividing by 2:** - 48 ÷ 2 = 24 - 24 ÷ 2 = 12 - 12 ÷ 2 = 6 - 6 ÷ 2 = 3 4. **3 is a prime number, so we divide by 3:** - 3 ÷ 3 = 1 5. **List all the factors:** - From the divisions, we can find the factors: - 1, 2, 3, 4 (2×2), 6 (2×3), 8 (2×2×2), 12 (4×3), 16 (2×2×2×2), 24 (8×3), 32 (16×2), 48 (24×2), 96 (48×2). **Set of factors of 96:** {1, 2, 3, 4, 6, 8, 12, 16, 24, 32, 48, 96} ### Summary of Factors - Factors of 88: {1, 2, 4, 8, 11, 22, 44, 88} - Factors of 105: {1, 3, 5, 7, 15, 21, 35, 105} - Factors of 96: {1, 2, 3, 4, 6, 8, 12, 16, 24, 32, 48, 96}
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