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A student got 20% marks and failed by 30...

A student got `20%` marks and failed by 30 marks. Another student got `32%` marks and scored 42 marks more than passing mark. Find the passing mark in an examination.

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To find the passing marks in the examination, we can follow these steps: ### Step 1: Define the variables Let the full marks of the examination be \( x \). ### Step 2: Set up the equations based on the information given 1. The first student got 20% of the full marks and failed by 30 marks. This can be expressed as: \[ \text{Marks obtained by first student} + 30 = \text{Passing marks} \] Therefore, we can write: \[ 0.2x + 30 = P \quad \text{(Equation 1)} \] 2. The second student got 32% of the full marks and scored 42 marks more than the passing marks. This can be expressed as: \[ \text{Marks obtained by second student} - 42 = \text{Passing marks} \] Therefore, we can write: \[ 0.32x - 42 = P \quad \text{(Equation 2)} \] ### Step 3: Set the two equations equal to each other Since both equations represent the passing marks \( P \), we can set them equal to each other: \[ 0.2x + 30 = 0.32x - 42 \] ### Step 4: Solve for \( x \) 1. Rearranging the equation gives: \[ 30 + 42 = 0.32x - 0.2x \] \[ 72 = 0.12x \] 2. Now, divide both sides by 0.12 to find \( x \): \[ x = \frac{72}{0.12} = 600 \] ### Step 5: Find the passing marks \( P \) Now that we have the full marks \( x = 600 \), we can substitute this value back into either Equation 1 or Equation 2 to find the passing marks. Using Equation 1: \[ P = 0.2 \times 600 + 30 \] \[ P = 120 + 30 = 150 \] ### Final Answer The passing marks in the examination are \( \boxed{150} \). ---
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