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A house-owner was having his house paint...

A house-owner was having his house painted. He was advised that he would require 25 kg of paint. Allowing for `15%` wastage and assuming that the paint is available in 2 kg cans, what would be the cost of paint purchased, if one can costs Rs. 16?

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To solve the problem step by step, we will follow these calculations: ### Step 1: Calculate the total amount of paint required including wastage. The house-owner needs 25 kg of paint, and we need to account for 15% wastage. \[ \text{Wastage} = 25 \times \frac{15}{100} = 3.75 \text{ kg} \] Now, add the wastage to the original amount of paint required: \[ \text{Total paint required} = 25 + 3.75 = 28.75 \text{ kg} \] ### Step 2: Determine the number of cans needed. The paint is available in 2 kg cans. To find out how many cans are needed, we divide the total paint required by the size of each can: \[ \text{Number of cans} = \frac{28.75}{2} = 14.375 \] Since we cannot purchase a fraction of a can, we round up to the nearest whole number: \[ \text{Number of cans needed} = 15 \] ### Step 3: Calculate the total cost of the paint. Each can costs Rs. 16. Therefore, the total cost can be calculated as follows: \[ \text{Total cost} = \text{Number of cans} \times \text{Cost per can} = 15 \times 16 = 240 \text{ Rs.} \] ### Final Answer: The total cost of the paint purchased is Rs. 240. ---
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