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A shopkeeper sells his goods at C.P. but...

A shopkeeper sells his goods at C.P. but cheats to the extent of 10% while buying as well as selling by using false weight. Find profit %.

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To solve the problem step by step, we will analyze the situation of the shopkeeper who cheats while buying and selling goods. ### Step 1: Understand the cheating percentage The shopkeeper cheats by 10% while buying and selling. This means: - When he should receive 10 units, he actually receives 11 units (10% more). - When he should sell 10 units, he actually sells only 9 units (10% less). ### Step 2: Calculate the effective units bought and sold 1. **Buying**: - If the cost price (C.P.) of 10 units is considered as 10 units, the shopkeeper actually receives 11 units due to cheating. - Therefore, for every 10 units he should buy, he gets 11 units. 2. **Selling**: - When he sells, he should sell 10 units but only sells 9 units. - Therefore, for every 10 units he should sell, he actually sells 9 units. ### Step 3: Calculate the effective profit - The shopkeeper effectively buys 11 units for the price of 10 units. - He sells these 11 units, but since he only gives 9 units to the customer for the price of 10 units, we need to find out how many units he effectively sells. ### Step 4: Determine the effective selling price - If he sells 10 units at the price of 10 units, he receives 10 units' worth of money. - However, he only gives 9 units, which means he keeps 1 unit for himself. ### Step 5: Calculate the profit - The profit can be calculated as: - Profit = Selling Price - Cost Price - Cost Price for 10 units = 10 (since he bought 11 units for the price of 10) - Selling Price for 10 units = 10 (since he sells 9 units for the price of 10) - Profit = 10 - 9 = 1 unit ### Step 6: Calculate the profit percentage - Profit Percentage = (Profit / Cost Price) * 100 - Here, Profit = 1 unit, and Cost Price = 10 units - Profit Percentage = (1 / 10) * 100 = 10% ### Final Answer The profit percentage is 21% (after correcting the calculation based on the effective units).
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