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A person purchased 3 cows and 8 goats fo...

A person purchased 3 cows and 8 goats for Rs 47200 If he had purchased 8 cows and 3 gots then he would have to give Rs 53000 more . Find cost price of each cow.

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To find the cost price of each cow, we can set up the problem using algebra. Let's denote the cost price of each cow as \( C \) and the cost price of each goat as \( G \). ### Step 1: Set up the equations based on the information given. From the problem, we have two scenarios: 1. The cost of 3 cows and 8 goats is Rs. 47,200. \[ 3C + 8G = 47200 \quad \text{(Equation 1)} \] 2. The cost of 8 cows and 3 goats is Rs. 53,000 more than the first scenario, which means: \[ 8C + 3G = 47200 + 53000 = 100200 \quad \text{(Equation 2)} \] ### Step 2: Solve the equations. Now we have two equations: 1. \( 3C + 8G = 47200 \) 2. \( 8C + 3G = 100200 \) We can solve these equations simultaneously. ### Step 3: Multiply the first equation to align coefficients. To eliminate \( G \), we can multiply Equation 1 by 3 and Equation 2 by 8: \[ 9C + 24G = 141600 \quad \text{(Equation 3)} \] \[ 64C + 24G = 801600 \quad \text{(Equation 4)} \] ### Step 4: Subtract the equations to eliminate \( G \). Now, we subtract Equation 3 from Equation 4: \[ (64C + 24G) - (9C + 24G) = 801600 - 141600 \] This simplifies to: \[ 55C = 660000 \] ### Step 5: Solve for \( C \). Now, divide both sides by 55: \[ C = \frac{660000}{55} = 12000 \] ### Conclusion: The cost price of each cow is Rs. 12,000. ---
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ADVANCED MATHS BY ABHINAY MATHS ENGLISH-PROFIT & LOSS-Questions
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