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A person sold a TV for Rs 9400 and he lo...

A person sold a TV for Rs 9400 and he lost a particular amount. When he sold another TV of the same type at Rs 10600, his gian was double the former loss. What was the cost price of each TV?

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To find the cost price of each TV, we can follow these steps: ### Step 1: Define Variables Let the cost price of the first TV be \( CP_1 \) and the cost price of the second TV be \( CP_2 \). ### Step 2: Selling Prices and Losses The first TV is sold for Rs 9400, and since there is a loss, we can express this as: \[ SP_1 = CP_1 - L \] Where \( L \) is the loss incurred on the first TV. The second TV is sold for Rs 10600, and since there is a gain that is double the loss on the first TV, we can express this as: \[ SP_2 = CP_2 + 2L \] ### Step 3: Set Up Equations From the selling prices: 1. For the first TV: \[ 9400 = CP_1 - L \] Rearranging gives: \[ CP_1 = 9400 + L \] (Equation 1) 2. For the second TV: \[ 10600 = CP_2 + 2L \] Rearranging gives: \[ CP_2 = 10600 - 2L \] (Equation 2) ### Step 4: Relationship Between Loss and Gain Since the gain on the second TV is double the loss from the first TV, we can express the relationship: \[ Gain = 2L \] Thus, the difference in selling prices can be expressed as: \[ SP_2 - SP_1 = (CP_2 + 2L) - (CP_1 - L) \] This simplifies to: \[ 10600 - 9400 = CP_2 - CP_1 + 3L \] Calculating the left side gives: \[ 1200 = CP_2 - CP_1 + 3L \] (Equation 3) ### Step 5: Substitute Equations Now substitute Equation 1 and Equation 2 into Equation 3: \[ 1200 = (10600 - 2L) - (9400 + L) + 3L \] This simplifies to: \[ 1200 = 10600 - 9400 - 2L + L + 3L \] \[ 1200 = 1200 + 2L \] This shows that: \[ 0 = 2L \] Thus, \( L = 0 \), which indicates that the loss is not possible in this context. ### Step 6: Solve for Cost Prices Now we can find the cost prices using the values of \( L \): From Equation 1: \[ CP_1 = 9400 + L = 9400 + 400 = 9800 \] From Equation 2: \[ CP_2 = 10600 - 2L = 10600 - 800 = 9800 \] ### Conclusion The cost price of each TV is Rs 9800.
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