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(A + B) can do a piece of work in 10 day...

(A + B) can do a piece of work in 10 days. A works `2(1)/(2)` days and B works for `8(1)/(2)` days, then half of the work has been completed. In how many days will B do this work alone ?

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The correct Answer is:
To solve the problem step by step, we will use the information given in the question. ### Step 1: Determine the total work done by A and B together. Given that A + B can complete the work in 10 days, we can express the total work (W) in terms of their combined work rate. \[ \text{Work Rate of (A + B)} = \frac{1}{10} \text{ (work per day)} \] Thus, the total work can be calculated as: \[ W = \text{Work Rate} \times \text{Time} = \frac{1}{10} \times 10 = 1 \text{ (whole work)} \]
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