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A takes 24 days more than B and 32 days ...

A takes 24 days more than B and 32 days more than C to complete a work. C works as much as (A + B) works together. In how many days will A, B and C alone complete this work ?

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To solve the problem step by step, let's denote the number of days taken by A, B, and C to complete the work as follows: - Let the number of days taken by C to complete the work be \( x \). - According to the problem, A takes 32 days more than C, so A takes \( x + 32 \) days. - A also takes 24 days more than B, so B takes \( (x + 32) - 24 = x + 8 \) days. Now we have: - Days taken by C = \( x \) - Days taken by A = \( x + 32 \) - Days taken by B = \( x + 8 \) Next, we know from the problem that C works as much as A and B together. This means that the work done by C in \( x \) days is equal to the work done by A and B together in the same time. The work done can be expressed in terms of their rates: - Rate of A = \( \frac{1}{x + 32} \) (work per day) - Rate of B = \( \frac{1}{x + 8} \) (work per day) - Rate of C = \( \frac{1}{x} \) (work per day) According to the problem, the work done by C in \( x \) days is equal to the work done by A and B in the same time: \[ \frac{x}{x} = \frac{x}{x + 32} + \frac{x}{x + 8} \] This simplifies to: \[ 1 = \frac{x}{x + 32} + \frac{x}{x + 8} \] To combine the fractions on the right-hand side, we find a common denominator: \[ 1 = \frac{x(x + 8) + x(x + 32)}{(x + 32)(x + 8)} \] This simplifies to: \[ 1 = \frac{x^2 + 8x + x^2 + 32x}{(x + 32)(x + 8)} \] \[ 1 = \frac{2x^2 + 40x}{(x + 32)(x + 8)} \] Cross-multiplying gives: \[ (x + 32)(x + 8) = 2x^2 + 40x \] Expanding the left-hand side: \[ x^2 + 40x + 256 = 2x^2 + 40x \] Subtracting \( 2x^2 + 40x \) from both sides: \[ x^2 + 40x + 256 - 2x^2 - 40x = 0 \] This simplifies to: \[ -x^2 + 256 = 0 \] Thus, we have: \[ x^2 = 256 \implies x = 16 \] Now we can find the days taken by A, B, and C: - Days taken by C = \( x = 16 \) days - Days taken by B = \( x + 8 = 16 + 8 = 24 \) days - Days taken by A = \( x + 32 = 16 + 32 = 48 \) days **Final Answers:** - A takes 48 days to complete the work. - B takes 24 days to complete the work. - C takes 16 days to complete the work.
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ADVANCED MATHS BY ABHINAY MATHS ENGLISH-TIME & WORK -QUESTIONS
  1. A takes 5(1)/(3) days more than (A + B) together to complete a work. ...

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  2. A takes 7 days more than B and 16 days more than C to complete a work....

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  3. A takes 24 days more than B and 32 days more than C to complete a work...

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  4. A takes 5 days more than B and 9 days more than C to complete a work. ...

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  5. A takes 6 hours more than (A + B + C) together to complete a work. B t...

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  6. A and B together can do a piece of work in 12 days. While B and C toge...

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  7. (A + B) together can do a piece of work in 12 days. While (B + C) toge...

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  8. A takes as much time as B and C together to complete a work. While A a...

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  9. A is 40 % more efficient than B. If B can complete this work in 24 day...

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  10. A works thrice as much as B. If A can complete this work in 12 days, t...

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  11. B works four times as much as A. If B takes 15 days less than A to com...

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  12. A is 40 % more efficient than B and B is 20 % less efficient than C. I...

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  13. Ratio of efficiency of P and Q is 3 : 4. Find the ratio of number of d...

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  14. Efficiency of A is (3)/(4) of B's efficiency and B's efficiency is 80...

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  15. A and B can finish a certain piece of work in 4 days. If A reduces his...

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  16. The ratio of efficiency of A and B is 3 : 5 and that of B and C is 2 :...

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  17. A and B working together can finish certain piece of work in 10 days. ...

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  18. A takes three times as long as (B + C) together to complete a work. B ...

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  19. B takes two times as long as (A + C) together to complete a work. C ta...

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  20. A does half as much work as B in one-sixth of the time.If together the...

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