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Efficiency of A is (3)/(4) of B's effic...

Efficiency of A is `(3)/(4)` of B's efficiency and B's efficiency is 80% of C's efficiency. If A takes 120 more days than that of B and C working together to finish a certain piece of work. Then in how many days working together they will finish the work?

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To solve the problem step by step, let's denote the efficiencies of A, B, and C as follows: 1. **Define the efficiencies**: - Let B's efficiency be \( b \). - Then A's efficiency is \( \frac{3}{4}b \). - B's efficiency is 80% of C's efficiency, so \( b = 0.8c \) or \( c = \frac{b}{0.8} = \frac{5}{4}b \). 2. **Calculate combined efficiency of B and C**: - The efficiency of B is \( b \). - The efficiency of C is \( \frac{5}{4}b \). - Therefore, the combined efficiency of B and C is: \[ b + \frac{5}{4}b = \frac{4}{4}b + \frac{5}{4}b = \frac{9}{4}b \] 3. **Determine the time taken by A and B+C**: - Let \( T \) be the time taken by B and C to complete the work together. - The work done by B and C in \( T \) days is: \[ \text{Work} = \text{Efficiency} \times \text{Time} = \frac{9}{4}b \times T \] - A takes 120 days more than B and C, so the time taken by A is \( T + 120 \). - The work done by A in \( T + 120 \) days is: \[ \text{Work} = \text{Efficiency} \times \text{Time} = \frac{3}{4}b \times (T + 120) \] 4. **Set the work equations equal**: - Since both expressions represent the same total work, we can set them equal: \[ \frac{9}{4}b \times T = \frac{3}{4}b \times (T + 120) \] 5. **Cancel \( b \) and simplify**: - Dividing both sides by \( \frac{3}{4}b \) (assuming \( b \neq 0 \)): \[ \frac{9}{4}T = T + 120 \] - Multiply through by 4 to eliminate the fraction: \[ 9T = 4T + 480 \] - Rearranging gives: \[ 9T - 4T = 480 \implies 5T = 480 \implies T = \frac{480}{5} = 96 \] 6. **Calculate total time working together**: - The total time taken by B and C working together is \( T = 96 \) days. - Therefore, the total time taken by A, B, and C working together is: \[ T + 120 = 96 + 120 = 216 \text{ days} \] 7. **Final answer**: - The total time taken by A, B, and C working together to finish the work is **216 days**.
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