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A takes 4 hours more than that of A and ...

A takes 4 hours more than that of A and B working together to finish certain piece of work. While B takes 9 hours more than that of A and B working together. Then find in how many hours A and B working together can finish the work?

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To solve the problem, we need to find out how many hours A and B together can finish the work. Let's denote the time taken by A and B working together as \( x \) hours. ### Step-by-Step Solution: 1. **Define the Variables**: - Let \( x \) be the time taken by A and B working together to complete the work. - Then, A takes \( x + 4 \) hours to finish the work alone. - B takes \( x + 9 \) hours to finish the work alone. 2. **Calculate the Work Done**: - The work done by A in one hour is \( \frac{1}{x + 4} \). - The work done by B in one hour is \( \frac{1}{x + 9} \). - The work done by A and B together in one hour is \( \frac{1}{x} \). 3. **Set Up the Equation**: - According to the work rates, the combined work done by A and B in one hour can be expressed as: \[ \frac{1}{x} = \frac{1}{x + 4} + \frac{1}{x + 9} \] 4. **Find a Common Denominator**: - The common denominator for the right side of the equation is \( (x + 4)(x + 9) \). - Rewrite the equation: \[ \frac{1}{x} = \frac{(x + 9) + (x + 4)}{(x + 4)(x + 9)} \] - Simplifying the numerator: \[ \frac{1}{x} = \frac{2x + 13}{(x + 4)(x + 9)} \] 5. **Cross-Multiply**: - Cross-multiplying gives: \[ (2x + 13)x = (x + 4)(x + 9) \] 6. **Expand Both Sides**: - Left side: \[ 2x^2 + 13x \] - Right side: \[ x^2 + 13x + 36 \] 7. **Set Up the Quadratic Equation**: - Now, equate both sides: \[ 2x^2 + 13x = x^2 + 13x + 36 \] - Simplifying gives: \[ 2x^2 - x^2 + 13x - 13x - 36 = 0 \] \[ x^2 - 36 = 0 \] 8. **Solve the Quadratic Equation**: - Factoring gives: \[ (x - 6)(x + 6) = 0 \] - Thus, \( x = 6 \) or \( x = -6 \) (we discard the negative solution since time cannot be negative). 9. **Conclusion**: - Therefore, A and B working together can finish the work in **6 hours**.
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