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A group of men decided to do a work in 1...

A group of men decided to do a work in 10 days, but 5 of them become absent. if the rest of the group did the work in 12 days, find the original number of men?

A

20

B

25

C

30

D

35

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we will follow these steps: ### Step 1: Define Variables Let the original number of men be \( x \). ### Step 2: Set Up the Work Equation According to the problem, the group of men decided to complete the work in 10 days. Therefore, the total work done can be represented as: \[ \text{Total Work} = \text{Number of Men} \times \text{Days} = x \times 10 = 10x \] ### Step 3: Adjust for Absentees When 5 men become absent, the number of men remaining is \( x - 5 \). The remaining men complete the work in 12 days. Thus, the total work done by the remaining men can be represented as: \[ \text{Total Work} = \text{Number of Remaining Men} \times \text{Days} = (x - 5) \times 12 \] ### Step 4: Set the Two Work Equations Equal Since the total work remains the same, we can set the two equations equal to each other: \[ 10x = (x - 5) \times 12 \] ### Step 5: Expand and Simplify the Equation Expanding the right side gives: \[ 10x = 12x - 60 \] ### Step 6: Rearrange the Equation Rearranging the equation to isolate \( x \): \[ 10x - 12x = -60 \] \[ -2x = -60 \] \[ 2x = 60 \] \[ x = 30 \] ### Step 7: Conclusion The original number of men is \( x = 30 \). Thus, the answer is **30**. ---
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