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The difference between the area of a squ...

The difference between the area of a square and that of an equilateral triangle on the same base is 1/4 `cm^(2)`. What is the length of side of triangle ?

A

`(4 - sqrt(3))^(1//2)` cm

B

`(4 + sqrt(3))^(1//2)` cm

C

`(4 - sqrt(3))^(-1//2)` cm

D

`(4 + sqrt(3))^(-1//2)` cm

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to find the length of the side of an equilateral triangle given that the difference between the area of a square and that of the triangle on the same base is \( \frac{1}{4} \, \text{cm}^2 \). ### Step-by-Step Solution: 1. **Define Variables**: Let the side length of the equilateral triangle be \( a \, \text{cm} \). Since the square and triangle share the same base, the side length of the square is also \( a \, \text{cm} \). 2. **Calculate the Area of the Square**: The area of the square is given by the formula: \[ \text{Area of square} = a^2 \] 3. **Calculate the Area of the Equilateral Triangle**: The area of an equilateral triangle is given by the formula: \[ \text{Area of triangle} = \frac{\sqrt{3}}{4} a^2 \] 4. **Set Up the Equation**: According to the problem, the difference between the area of the square and the area of the triangle is \( \frac{1}{4} \, \text{cm}^2 \): \[ a^2 - \frac{\sqrt{3}}{4} a^2 = \frac{1}{4} \] 5. **Simplify the Equation**: Combine the terms on the left side: \[ \left(1 - \frac{\sqrt{3}}{4}\right) a^2 = \frac{1}{4} \] To simplify \( 1 - \frac{\sqrt{3}}{4} \), we can express \( 1 \) as \( \frac{4}{4} \): \[ \left(\frac{4 - \sqrt{3}}{4}\right) a^2 = \frac{1}{4} \] 6. **Eliminate the Denominator**: Multiply both sides by \( 4 \) to eliminate the fraction: \[ (4 - \sqrt{3}) a^2 = 1 \] 7. **Solve for \( a^2 \)**: Divide both sides by \( (4 - \sqrt{3}) \): \[ a^2 = \frac{1}{4 - \sqrt{3}} \] 8. **Take the Square Root**: To find \( a \), take the square root of both sides: \[ a = \sqrt{\frac{1}{4 - \sqrt{3}}} \] 9. **Rationalize the Denominator**: To simplify further, multiply the numerator and denominator by \( 4 + \sqrt{3} \): \[ a = \sqrt{\frac{4 + \sqrt{3}}{(4 - \sqrt{3})(4 + \sqrt{3})}} = \sqrt{\frac{4 + \sqrt{3}}{16 - 3}} = \sqrt{\frac{4 + \sqrt{3}}{13}} \] ### Final Result: Thus, the length of the side of the equilateral triangle is: \[ a = \sqrt{\frac{4 + \sqrt{3}}{13}} \, \text{cm} \]
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