Home
Class 14
MATHS
graph of y=x+|x|...

graph of `y=x+|x|`

A

B

C

D

Text Solution

AI Generated Solution

The correct Answer is:
To graph the equation \( y = x + |x| \), we will analyze the equation step by step. ### Step 1: Understand the Absolute Value The absolute value function \( |x| \) is defined as: - \( |x| = x \) when \( x \geq 0 \) - \( |x| = -x \) when \( x < 0 \) ### Step 2: Break the Equation into Cases We will consider two cases based on the value of \( x \): **Case 1:** When \( x \geq 0 \) - Here, \( |x| = x \) - Substitute into the equation: \[ y = x + |x| = x + x = 2x \] **Case 2:** When \( x < 0 \) - Here, \( |x| = -x \) - Substitute into the equation: \[ y = x + |x| = x - x = 0 \] ### Step 3: Create a Table of Values Now, we can create a table of values for both cases to plot the graph. | \( x \) | \( y \) (for \( x \geq 0 \)) | \( y \) (for \( x < 0 \)) | |---------|-------------------------------|-----------------------------| | -2 | 0 | 0 | | -1 | 0 | 0 | | 0 | 0 | 0 | | 1 | 2 | 0 | | 2 | 4 | 0 | ### Step 4: Plot the Points - For \( x < 0 \) (from -2 to 0), the value of \( y \) is always 0. - For \( x = 0 \), \( y = 0 \). - For \( x \geq 0 \) (from 0 to 2), the value of \( y \) increases linearly as \( y = 2x \). ### Step 5: Draw the Graph - Draw a horizontal line along the x-axis for \( x < 0 \) where \( y = 0 \). - From \( x = 0 \) onwards, draw a line with a slope of 2, starting from the origin (0,0). ### Conclusion The graph of \( y = x + |x| \) consists of a horizontal line along the x-axis for \( x < 0 \) and a line with slope 2 for \( x \geq 0 \).
Promotional Banner

Topper's Solved these Questions

  • COMPOUND INTEREST

    ADVANCED MATHS BY ABHINAY MATHS ENGLISH|Exercise QUESTIONS |159 Videos
  • FREE MATHS LIVE MOCK 20

    ADVANCED MATHS BY ABHINAY MATHS ENGLISH|Exercise MULTIPLE CHOICE QUESTIONS |98 Videos

Similar Questions

Explore conceptually related problems

Draw the graphs of y=x-x/(|x|)

Draw the graphs of y=x+x/(|x|)

The distance between the highest point on the graph of y=-(x-1)(x-3) and the lowest point on the graph of y=x(x-4) is -

Draw the graph of y=(x-1)/(x^(2)) and hence the graph of y=(|x-1|)/(x^(2)) .

Draw the graph of y=||x|^(2)-2|x|-3|, if the graph for y=x^(2)-2x-3 is given.

Sketch the graph of y=min{|x|,|x-1|,|x+1|}.

Draw graph of y=cos x+|cos x|

Draw the graph of y = |x^(2) - 2x|-x .