If n is a 3 digit number and `n^(2)=---54` . Than how values are possilbe for n ?

n-digit number

IF n is a three digit number and last two digits of square of n are 54(n^(2) = …. 54), then how many values of n are possible ?

Let n be a 5 digit number such that n=304a2 and 3|n then a=

If n is an odd number greater than 1, then n(n^(2)-1) is

If N is natural number less than 100, then for how many values of N are the numbers 6N+1and15N+2 relatively prime?

If the sum of the digits of a number 10^(n) - 1 , where n is a natural number, is equal to 3798, then what is the value of n ?

A 3 digit palindrome is a 3 digit number (not starting with zero) which reads the same backwards as forwards For example, 242. The sim of all even 3 digit palindromes is 2^(n_(1))*3^(n_(2))*5^(n_(3))*7^(n_(4))*11^(n_(5))* value of n_(1)+n_(2)+n_(3)+n_(4)+n_(5) is