`1!+2!+3!+4!+ ----100!` divided by 5 . find Remainder .

x^(35) +3 is divided by x^(5)+1 , find remainder

If x^(2)+x+4 is divided by (x-1) , find the remainder

When (1!)^(1!) + (2!)^(2!) + (3!)^(3!) + ……+(100!)^(100!) is divided by 5, the remainder obtained is :

Is a two-digit integer 'x' dividible by 12? I. When 'x' is divided by 5, the remainder is 2. II. When 'x' is divided by 3, the remainder is 1.

When a natural number x is divided by 5, the remainder is 2. When a natural number y is divided by 5, the remainder is 4, The remainder is z when x+y is divided by 5. The value of (2z-5)/(3) is