`(10^(1)+10^(2)+10^(3)------+10^(100))/(6)` find R.

(10^(10)+10^(100)+10^(1000)+ -----+10^10000000000)/(7) find R.

(2^(35))/(10) Find R .

10^(-2)=1/100

Write the numeral whose expanded form is given below: ( i ) 6 xx 10^(4)+3 xx 10^(3)+0 xx 10^(2)+7 xx 10^(1)+8 xx 10^(0) ( ii ) 9 xx 10^(6)+7 xx 10^(5)+0 xx 10^(4)+3 xx 10^(3)+2 xx 10^(2)+9 xx 10^(1)+6 xx 10^(0) ( iii ) 8 xx 10^(5)+6 xx 10^(4)+4 xx 10^(3)+2 xx 10^(2)+9 xx 10^(1)+6 xx 10^(0)

The 100^(th) root of 10^((10^(10))) is

10xx10^(3)*2.2xx10^(-6)*(10)/(0.4)

If same tensile force is applied on two wires, there will an extension of 1xx10^(-3) m in them. The Young's moduli and radii of these wires are 10xx10^(10)N//m^(2) and 20xx10^(10)N//m^(2) and R_(1) and R_(2) respectively then R_(2) is equal to

10^(3)xx100^(3)+999999999=10^(?)+10^(?)