`(2^(76))/(96)` find R.

Let R be a relation such that R = {(1,4), (3,7), (4,5), (4,6), (7,6)} , find (i) R^(-1)OR^(-1) and (ii) (R^(-1)OR)^(-1)

If the coefficient so three consecutive terms in the expansion of (1+x)^(n) be 76,9 and 76 find n .

(96)^(2) =?

Let R be a relation defined by R={(9,8),(1,9),(9,6),(7,6),(2,7)} then R^(-1)oR is given by

Given that HCF (96,404) is 4, find the LCM ( 96,404)

What is the remainder when 2^(96) is divided by 96 ?