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If ax+by=1 and bx+ay=(2ab)/(a^(2)+b^(2))...

If `ax+by=1` and `bx+ay=(2ab)/(a^(2)+b^(2))` then `(x^(2)+y^(2))(a^(2)+b^(2))` is equal to

A

1

B

2

C

`0.5`

D

0

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