Using the laws of conservation of energy and momentum

Explanation

Applying laws of conservation of energy and momentum, we obtain
`mgDeltay=(mv_x^2)/2+(mv_y^2)/2+(MV^2)/2-MV=mv_x`

Noting that `Deltay =ayt^2//2,Deltax=a_xt^2//2,Deltax = bt^2//2,v_x=a_xt,v_y =a_yt and V = bt` and that `Deltay = (Deltax - DeltaX)` tan `alpha` we obtain after some simple transformations
`a_x=(M gsinalphacos alpha)/(M+m sin^2alpha)`
i.e. the same result as in Problem 3.7. The value of a, is obtained from these equations in a similar way. The reaction is obtained from the condition
`Q=ma=msqrt(a_x^2+a_y^2)`