Home
Class 12
PHYSICS
Find the lifting force of a balloon of 2...

Find the lifting force of a balloon of `2 xx 10^4 m^3` capacity filled with helium at the surface of the Earth and at an altitude of 10 km above sea level. The balloon's envelope is open underneath. For data on the properties of the Earth's atmosphere see `xi 26.10`, Table.

Text Solution

Verified by Experts

The correct Answer is:
`2 xx10^5N; 7 xx10^4 N`
The atmospheric pressure close to the Earth.s surface is, according to Table 26.3, equal to `1.01 xx 10^5` Pa, the air density is `1.23 kg//m^3` and the absolute temperature is 288 K. The helium pressure inside the envelope is the same, as the envelope communicates with the atmosphere. The density of helium in these conditions is `rho_(He) = pM//RT = 0.16 kg//m^3`. The list is equal to the difference between the Archimedean force and the force of gravity:
`F = (rho t - rho_(He))Vg`
Promotional Banner

Similar Questions

Explore conceptually related problems

The centripetal acceleration of a satellite that circles the earth at an altitude 400 km above see level is (g on the surface of earth is 10m//s^(2) , Radius of the earth is 6.4xx10^(6)m )

Find the magnitude of the acceleration due to gravity at the surface of the earth. ( M = 6 xx 10^(24) Kg, R = 6400 Km)

A satellite of mass 10 kg is placed initially in a temporary orbit 800 km above the surface of earth. The satellite is to be placed now in a permanent orbit at 2000 km above the surface of earth. Find the amount of workdone to move the satellite from temporary to permanent orbit. The radius of the earth is 6400 km and g = 10 ms^(-2) .

The critical speed of a satellite orbiting very close to the surface of the earth is [g=10 m//s^(2) and R=6.4xx10^(-6)m]

Assuming the radius of the earth to be 6.4xx10^(6) m calculate the time period T of a satellite for equatorial orbit at 1.4xx10^(3) km above the surface of the earth and the speed of the satellite in this orbit ?

Assuming the radius of the earth to be 6.5 xx 10^(6) m. What is the time period T and speed of satellite for equatorial orbit at 1.4 xx 10^(3) km above the surface of the earth.