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A uniform rod of length 2.0 m is suspend...

A uniform rod of length 2.0 m is suspended through an end and is set into oscillation with small amplitude under gravity. The time period of oscillation is approximately

A

1.60 s

B

1.80 s

C

2.00 s

D

2.40 s

Text Solution

Verified by Experts

The correct Answer is:
D

`T= 2pi sqrt((I_(0)+mh^(2))/(mg h))`
where `I_(0) = ml^(2)//12`
`h=(l)/(2)`
So, `T=2.40s`
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