The treatment of `CH_(3) MgX ` with `CH_(3)-=C-H` produces :

Options

A. `Ch_(3)-CH=CH_(2)`
B. `CH_(3) C -=C-CH_(3)`
C. `CH_(3)- overset(H)overset(|)C=overset(H)overset(|)C-CH_(3)`
D. `CH_(4)`

Explanation

To solve the problem of what happens when `CH₃MgX` (a Grignard reagent) reacts with `CH₃C≡CH` (a terminal alkyne), we can follow these steps:

### Step 1: Identify the Reactants
We have two reactants:
1. `CH₃MgX` - This is a Grignard reagent where `X` is a halogen (like Cl, Br, or I).
2. `CH₃C≡CH` - This is a terminal alkyne.

### Step 2: Understand the Reaction Mechanism
Grignard reagents are strong nucleophiles and can react with electrophiles. In this case, the terminal alkyne has a hydrogen atom that is acidic due to the sp-hybridized carbon.

### Step 3: Nucleophilic Attack
When `CH₃MgX` reacts with `CH₃C≡CH`, the nucleophilic carbon (from the Grignard reagent) will attack the hydrogen atom of the terminal alkyne. This leads to the formation of a new bond.

### Step 4: Formation of Products
The following occurs:
- The `H` from the terminal alkyne is removed and combines with the `CH₃` from `CH₃MgX` to form methane (`CH₄`).
- The remaining part of the alkyne, after losing the hydrogen, will become a carbanion (`C≡C⁻`) which will then bond with `MgX` to form `CH₃C≡C-MgX`.

### Step 5: Final Products
The final products of this reaction are:
1. Methane (`CH₄`)
2. A new Grignard compound (`CH₃C≡C-MgX`)

### Conclusion
Thus, the treatment of `CH₃MgX` with `CH₃C≡CH` produces methane (`CH₄`) and a Grignard compound (`CH₃C≡C-MgX`).