If y = 2x + K is a diameter to the circle `2(x^(2) + y^(2)) + 3x + 4y –1 = 0`, then K equals

Similar Questions

Explore conceptually related problems

If y = 2x + m is a diameter to the circle x^(2) + y^(2) + 3x + 4y - 1 = 0 , then find m

If line 2x - y + k = 0 is a diameter of circle x^(2) + y^(2) + 6x - 6y + 5 = 0 , then k =

The line x+3y=0 is a diameter of the circle x^(2)+y^(2)+6x+2y=0

The line x+3y=0 is a diameter of the circle x^(2)+y^(2)-6x+2y=0

One of the diameter of the circle x^(2)+y^(2)-2x+4y-4=0 , is

If y=3x+c is a tangent to the circle x^(2)+y^(2)-2x-4y-5=0, then c is equal to :

If x + y+ k =0 touches the circle x ^(2) + y^(2) -2x -4y + 3 =0, then k can be

If (1,2)(2,a) are extremities of a diameter of the circle x^(2)+y^(2)-3x-4y+6=0 then a=

If line 4x + 3y + k = 0 " touches circle " 2x^(2) + 2y^(2) = 5x , then k =