A truck and a car moving with the same KE are brought to rest by the application of brakes which provide equal retarding force. Which of them will come to rest in a shorter distance ?

A truck and a car moving with the same kinetic energy are brought to rest by the application of brakes which provide equal retarding forces. Which of them will come to rest in a shorter distance?

A lorry and a car moving with the same kinetic energy are brought to rest by the application of brakes which provides equal retarding forces. Which of them will come to rest in a shorter distance?

A lorry and a car, moving with the same kinetic energy are brought to rest by application of brakes which provied equal retarding forces. Which one of them will come to rest in a shorter distance ?

A lorry and a car moving with the same KE are brought to rest by applying the same retarding force. Then

A motor cycle and a car are moving on a horizontal road with the same velocity. If they are brought to rest by the application of brakes, which provided equal retarding forces, then

A truck and a car are brought to a hault by application of same braking force. Which one will come to stop in a shorter distance if they are moving with same (a) velocity (b) kinetic energy and (c) momentum ?

STATEMENT-1: A bus and a car having the same kinetic energy are brought to rest by the applications of brakes. Assume that on application of brakes, rotational motion of wheels ceases and both may stop in dead heat. because STATEMENT-2: Retardation for both bus and truck must be same.

Cars I and II, having masses m and 2m respectively, are moving with velocities 2v and v respectively. They are brought to rest by the application of breaks. The cars take the same time and cover the same distance before coming to rest. What is the ratio of change in kinetic energy of car I to that of car II ?

A truck and a car are moving with the same K.E. on a straight road. Their engines are simultaneously switched off. Which one will stop at a lesser distance ?

Two unequal masses P and Q moving along straight lines are brought to rest by applying equal retarding forces. If P moves twice the time as Q, but goes only (1//3)^(rd) of the distance covered by Q before coming to rest, the ratio of their initial velocities is