Home
Class 11
PHYSICS
The frequency v of the stretched string ...

The frequency v of the stretched string may depend on (i) the length of the vibrating segment 1 (ii) the tension in the string and (iii) the mass per unit length m. Show that `v prop 1/l sqrt(F/m)`.

Text Solution

AI Generated Solution

To show that the frequency \( v \) of a stretched string is proportional to \( \frac{1}{L} \sqrt{\frac{F}{m}} \), we will use dimensional analysis. Here are the steps: ### Step 1: Identify the variables We have three variables that affect the frequency \( v \): - \( L \): Length of the vibrating segment - \( F \): Tension in the string - \( m \): Mass per unit length of the string ...
Promotional Banner

Topper's Solved these Questions

  • DIMENSIONS

    ICSE|Exercise SHORT ANSWER QUESTIONS WITH ANSWERS|10 Videos

  • DIMENSIONS

    ICSE|Exercise LONG ANSWER QUESTIONS|3 Videos

  • COMPETITION CARE UNIT

    ICSE|Exercise OBJECTIVE QUESTIONS FROM PREVIOUS IAS EXAMINATIONS |50 Videos

  • DYNAMICS

    ICSE|Exercise SHORT ANSWER QUESTIONS WITH ANSWERS|12 Videos

Similar Questions

Explore conceptually related problems

The frequency (f) of a stretched string depends upen the tension F (dimensions of form ) of the string and the mass per unit length mu of string .Derive the formula for frequency

The frequency of vibration of string depends on the length L between the nodes, the tension F in the string and its mass per unit length m. Guess the expression for its frequency from dimensional analysis.

Derive an expression for the velocity of pulse in a in stretched in string under a tension T and mu is the mass per unit length of the sting.

In each of the four situations of column-I , a stretched string or an organ pipe is given along with the required data. In case of strings the tension in string is T=102.4 N and the mass per unit length of string is 1g/m. Speed of sound in air is 320 m/s. Neglect end corrections.The frequencies of resonance are given in column-II.Match each situation in column-I with the possible resonance frequencies given in Column-II.

A 5.5 m length of string has a mass of 0.035 kg. If the tension in the string is 77 N the speed of a wave on the string is

Two strings of the same length but different mass per unit length are used to suspend a rod whose density varies as rho=rho_(0)[1+alphax] as shown in the figure. The frequency of standing waves produced in the string is in the ratio n : 1 , when both the strings are vibrating in their fundamental mode. If the mass per unit length of string (l) is mu_(0) , calculate the mass per unit length of the other string.

The velocity of transverse wave in a string is v = sqrt( T//m) where T is the tension in the string and m is the mass per unit length . If T = 3.0 kgf , the mass of string is 25g and length of the string is v = 1.000 m , then the percentage error in the measurement of velocity is

A transverse wave is propagating on a stretched string of mass per unit length 32 gm^(-1) . The tension on the string is 80 N. The speed of the wave over the string is

A string tied between x = 0 and x = l vibrates in fundamental mode. The amplitude A , tension T and mass per unit length mu is given. Find the total energy of the string.

String-1 is connected with string-2. The mass per unit length in string-1 is mu_1 and the mass per unit length in string-2 is 4mu_1 . The tension in the strings is T. A travelling wave is coming from the left. What fraction of the energy in the incident wave goes into string-2 ?