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The time period of oscillation T of a sm...

The time period of oscillation T of a small drop of liquid under surface tension depends upon the density `rho`, the radius r and surface tension `sigma`. Using dimensional analysis show that `T prop sqrt((rhor^(3))/(sigma))`

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To solve the problem using dimensional analysis, we need to express the time period \( T \) in terms of the given quantities: density \( \rho \), radius \( r \), and surface tension \( \sigma \). We will follow these steps: ### Step 1: Identify the dimensions of the given quantities 1. **Density \( \rho \)**: The dimension of density is given by mass per unit volume. \[ [\rho] = M L^{-3} \] ...
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