`MgCl_2`

Dow's process of extraction of Mg involves extraction of Mg from sea water. Sea water is concentrated in sun-light and is then treated with slaked lime. Magnesium hydroxide is heated in a stream of HCl to give MgCl_(2) which is electrolysed to discharge Mg. The mixture is in the ratio 35% MgCl_(2)+50% NaCl+15% CaCl_(2) . NaCl and CaCl_(2) are added to lower the fusion temperature and to increases the conductance. Mg^(2+) +Ca(OH)_(2) to Mg(OH)_(2)+Ca^(2+) Mg(OH)_(2)+2HCl to MgCl_(2)+2H_(2)O(l) Electrolysis of fused MgCl_(2) hArr Mg^(2+)+2Cl Mg^(2+)+2e^(-) to Mg ( At Cathode) 2Cl^(-) to Cl_(2)+2e^(-) (At Anode) Mg electrolysed is protected from atmospheric oxidation by a blanket of inert gases. In the hydrated chloride of Mg the value of x is :

Dow's process of extraction of Mg involves extraction of Mg from sea water. Sea water is concentrated in sun-light and is then treated with slaked lime. Magnesium hydroxide is heated in a stream of HCl to give MgCl_(2) which is electrolysed to discharge Mg. The mixture is in the ratio 35% MgCl_(2)+50% NaCl+15% CaCl_(2) . NaCl and CaCl_(2) are added to lower the fusion temperature and to increases the conductance. Mg^(2+) +Ca(OH)_(2) to Mg(OH)_(2)+Ca^(2+) Mg(OH)_(2)+2HCl to MgCl_(2)+2H_(2)O(l) Electrolysis of fused MgCl_(2) hArr Mg^(2+)+2Cl Mg^(2+)+2e^(-) to Mg ( At Cathode) 2Cl^(-) to Cl_(2)+2e^(-) (At Anode) Mg electrolysed is protected from atmospheric oxidation by a blanket of inert gases. Molten mixutre of NaCl and CaCl_(2) is added to the heated MgCl_(2) because :

Why is MgCl2 more soluble in water than AICI_3 ?

Given, the enthalpy of formation of MgCl_((s)) is -125 kJ mol^(-1) and the entahpy of formation of MgCl_(2(s)) is -642kJ mol^(-1) . Predict whether MgCl will undergo disproportionnation or not? If yes, calculate the enthalpy of disproportion.