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If 3x^(2) + 2alphaxy + 2y^(2) + 2ax - 4y...

If `3x^(2) + 2alphaxy + 2y^(2) + 2ax - 4y+1` can be resolved into two linear factors, Prove that '`alpha`' is a root of the equation `x^2 + 4ax + 2a^2 + 6 = 0`

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