Home
Class 12
MATHS
How many numbers between 10 and 10,000 c...

How many numbers between 10 and 10,000 can be formed by using the digits 1, 2, 3, 4, 5 if
Digits can be repeated

Text Solution

AI Generated Solution

The correct Answer is:
To find how many numbers between 10 and 10,000 can be formed using the digits 1, 2, 3, 4, and 5 with repetition allowed, we can break it down into three cases based on the number of digits in the numbers: 2-digit numbers, 3-digit numbers, and 4-digit numbers. ### Step 1: Count 2-digit numbers - A 2-digit number can be represented as \( AB \), where \( A \) is the first digit (tens place) and \( B \) is the second digit (units place). - The first digit \( A \) can be any of the 5 digits (1, 2, 3, 4, 5). - The second digit \( B \) can also be any of the 5 digits (1, 2, 3, 4, 5). - Therefore, the total number of 2-digit numbers is: \[ 5 \times 5 = 25 \] ### Step 2: Count 3-digit numbers - A 3-digit number can be represented as \( ABC \), where \( A \) is the first digit (hundreds place), \( B \) is the second digit (tens place), and \( C \) is the third digit (units place). - The first digit \( A \) can be any of the 5 digits. - The second digit \( B \) can also be any of the 5 digits. - The third digit \( C \) can also be any of the 5 digits. - Therefore, the total number of 3-digit numbers is: \[ 5 \times 5 \times 5 = 125 \] ### Step 3: Count 4-digit numbers - A 4-digit number can be represented as \( ABCD \), where \( A \) is the first digit (thousands place), \( B \) is the second digit (hundreds place), \( C \) is the third digit (tens place), and \( D \) is the fourth digit (units place). - The first digit \( A \) can be any of the 5 digits. - The second digit \( B \) can also be any of the 5 digits. - The third digit \( C \) can also be any of the 5 digits. - The fourth digit \( D \) can also be any of the 5 digits. - Therefore, the total number of 4-digit numbers is: \[ 5 \times 5 \times 5 \times 5 = 625 \] ### Step 4: Total numbers between 10 and 10,000 - Now, we add the total numbers from each case: \[ \text{Total} = \text{2-digit numbers} + \text{3-digit numbers} + \text{4-digit numbers} \] \[ \text{Total} = 25 + 125 + 625 = 775 \] Thus, the total number of numbers that can be formed between 10 and 10,000 using the digits 1, 2, 3, 4, and 5 with repetition allowed is **775**.
Promotional Banner

Topper's Solved these Questions

  • COMBINATORICS

    RESONANCE|Exercise Self practice problems|33 Videos
  • COMBINATORICS

    RESONANCE|Exercise Exercise-1 (Part-I: Pre RMO)|15 Videos
  • APPLICATION OF DERIVATIVES

    RESONANCE|Exercise High Level Problems (HLP)|33 Videos
  • DEFINITE INTEGRATION & ITS APPLICATION

    RESONANCE|Exercise High Level Problem|37 Videos

Similar Questions

Explore conceptually related problems

How many numbers greater than 50,000 can be formed by using the digits 2,5,5,6,7?

How many numbers between 5000 and 10,000 can be formed using the digits 1,2,3,4,5,6,7,8,9, each digit appearing not more than once in each number?

How many numbers between 100 and 1000 can be formed with digits 1,2,3,4,5,6,7, no digit being repeated?

How many numbers each ying between 1000 and 10000 can be formed wilth the digits 0,1,2,3,4,5, no digit being repeated?

How many numbers between 400 and 1000 can be formed with the digits 0,2,3,4,5,6 I no digit is repeated in the same number?

How many numbers each lying between 100 and 1000 can be formed with the digits 2,3,4,0,8,9, no digit being repeated?