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Which number is larger (1.3)^(2000) or 6...

Which number is larger `(1.3)^(2000) or 600`

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To determine which number is larger between \( (1.3)^{2000} \) and \( 600 \), we can follow these steps: ### Step 1: Rewrite \( (1.3)^{2000} \) We can express \( 1.3 \) as \( 1 + 0.3 \). Therefore, we can rewrite \( (1.3)^{2000} \) as: \[ (1.3)^{2000} = (1 + 0.3)^{2000} \] ### Step 2: Use the Binomial Theorem We can apply the Binomial Theorem to expand \( (1 + 0.3)^{2000} \): \[ (1 + 0.3)^{2000} = \sum_{k=0}^{2000} \binom{2000}{k} (0.3)^k \] This expansion gives us: \[ = \binom{2000}{0} (0.3)^0 + \binom{2000}{1} (0.3)^1 + \binom{2000}{2} (0.3)^2 + \ldots + \binom{2000}{2000} (0.3)^{2000} \] ### Step 3: Calculate the First Few Terms Calculating the first few terms of the expansion: - The first term is \( \binom{2000}{0} (0.3)^0 = 1 \). - The second term is \( \binom{2000}{1} (0.3)^1 = 2000 \times 0.3 = 600 \). - The third term is \( \binom{2000}{2} (0.3)^2 = \frac{2000 \times 199}{2} \times (0.3)^2 = \frac{2000 \times 199}{2} \times 0.09 = 199 \times 300 = 59700 \). ### Step 4: Sum the Terms Now, we can sum the first few terms: \[ (1.3)^{2000} \approx 1 + 600 + 59700 + \ldots \] Clearly, the sum of these terms is significantly greater than \( 600 \). ### Step 5: Conclusion Since the expansion of \( (1.3)^{2000} \) gives us a sum that is greater than \( 600 \), we conclude that: \[ (1.3)^{2000} > 600 \] Thus, \( (1.3)^{2000} \) is larger than \( 600 \). ---
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