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A golfer standing on the ground hits a b...

A golfer standing on the ground hits a ball with a velocity of 52m/s at an angle `theta` above the horizontal if `tantheta=(5)/(12)` find the time for which the ball is at least 15m above the ground? `(g=10m//s^(2))`

Text Solution

Verified by Experts

`v_(x) = sqrt(u_(y)^(2)-2gy)`

`= sqrt(52xx52xx(5xx5)/(13xx13) - 2xx10xx15) = sqrt(16xx25-300) = 10`
`Deltat = (2u_(y))/(10)= (2xx10)/(10) =` 2s
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