A particle is projected from the ground with an initial speed v at an angle `theta` with horizontal. The average velocity of the particle between its point of projection and highest point of trajectory is

Explanation

R/2
`vecv_(avg) = (vecv+vecu)/(2) = (u cos theta hat(i) +(u cos theta hat(i)+u sin theta hat(j)))/(2)`
` v_(av) = (v)/(2)sqrt(1+3cos^(2)theta)`