A ball of 200g is at one end of a string of length 20cm. It is revolved in a horizontal circle at an angular frequency of 6 rpm. Find (i) the angular velocity, (ii) the linear velocity, (iii) the centripetal acceleration,

Explanation

(i) The angular velocity ,
`omega = (2piN)/(t) = (2pixx6)/(60) = (pi)/(5) = 0.6284 rad s^(-1)`.
(ii) The linear velocity, `v = romega`
`=0.20xx0.6284 = 0.1257m s^(-1)`
(iii) The centripetal acceleration, `a_( c) = r omega^(2)`
`=0.20xx(0.6284)^(2)=0.0790m s^(-2)`.