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When forces F(1), F(2), F(3) are acting ...

When forces `F_(1), F_(2), F_(3)` are acting on a particle of mass m such that `F_(2) and F_(3)` are mutually perpendicular, then the particle remains stationary, If the forces `F_(1)` is now removed then acceleration of the particle is

A

`F_(1)//m`

B

`F_(1) F_(3) //mF_(1)`

C

`(F_(2) - F_(3))//m`

D

`F_(2)//m`

Text Solution

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The correct Answer is:
A
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